Email us for help
Loading...
Premium support
Log Out
Our Terms of Use and Privacy Policy have changed. We think you'll like them better this way.
OVERSTANDING REMOVES MISUNDERSTANDING
GUARANTEED WEALTH; HEALTH; WISDOM AND IS "toe-curling" RELATIONSHIPS ARE YOURS IF YOU OVER-STAND!
Simple harmonic motion Atoms connected via chemical bonds are equivalent to masses connected by springs. We can describe these using Hooke’s law (Q is a displacement of an atom away from eqn position) From Newton’s second law Where m is the reduced mass Thus Find a general solution where F = -kQ F = m d2 Q dt2 m d2 Q dt2 +kQ = 0 Q(t)= Acos(wvibt) wvib = k m; Insert potential into time independent Schrodinger equation: To find quantized solutions V(x) = 1 2 kx2 k = d2 V dx2 æ è ç ö ø ÷ From classical to quantum V(x) = V(0) + x dV dx æ è ç ö ø ÷+ 1 2 x2 d2 V dx2 æ è ç ö ø ÷ + 1 3! x3 d3 V dx3 æ è ç ö ø ÷ + ... If two nuclei are slightly displaced from equilibrium positions (x = R - Re), can express their potential energy in a Taylor series: Not interested in absolute potential, so set V(0) = 0. At equilibrium, dV/dx = 0 (a potential minimum). Providing displacement is small, third order term can be neglected. We can therefore write: EY(x) = - 2 2m Ñ2 +V(x) é ë ê ù û úY(x) En = wvib (n+ 1 2 ) his creates a ladder of vibrational modes This is well-known case of a harmonic oscillator. The energy of a quantum-mechanical harmonic oscillator is quantized and limited to the values. Selection rules dictate that harmonic Oscillator transitions are only allowed for Dn = ± 1 En = (n+ 1 2 ) wvib 0 1 2 3 4 5 6 7 8 Displacement (x) Energy Potential energy V wvib V(x) = 1 2 kx, Molecules have many different vibrational modes O C O O C O Asymmetric stretch mode O C O Bending mode CO O Symmetric stretch mode (100)